Asked by: Joanna

'The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom.'

So a cesium atomic clock would make just over 9 billion oscillations_per _second (OPS). Finding how many oscillations_per_day (OPD) is just a matter of multiplication:

OPD = OPS x 60 x 60 x 24

Where OPD is oscillations per day, and OPS is oscillations per second.

So we find out that the number of oscillations per second is:

That's 7.94 x 10

Answered by: Yasar Safkan, Ph.D., Sofware Engineer, Noktalar A.S., Istanbul, Turkey

'A theory with mathematical beauty is more likely to be correct than an ugly one that fits some experimental data. God is a mathematician of a very high order, and He used very advanced mathematics in constructing the universe.'**Paul Dirac**

(*1902-1984*)

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