Asked by: Brad Nelson

Centripetal acceleration = 9.81 m/s

The centripetal acceleration is, a:

a=r x w

Where r is the Earthï¿½s radius (in our case the radius at the equator), and w is the angular velocity.

Let a = 9.81 m/s

9.81 = 6.4 x 10

Therefore w = 0.00124 rad/s

This is how fast the Earth would need to rotate to get centripetal acceleration at the equator equal to 9.81 m/s

So if we use this value in this equation:

w = 2/T

Where w is the same as before, the numerator is constant, and T is the time for rotation or the period.

If we put our value of omega (angular velocity) into the equation we find that T = 5074.99 seconds or 1.409 hours. This means that the Earth would need to rotate with a

Answered by: Dan Summons, Physics Undergrad Student, UOS, Souhampton

'You cannot hope to build a better world without improving the individuals. To that end each of us must work for his own improvement, and at the same time share a general responsibility for all humanity, our particular duty being to aid those to whom we think we can be most useful.'**Marie Curie**

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