Asked by: Brad Nelson

Centripetal acceleration = 9.81 m/s

The centripetal acceleration is, a:

a=r x w

Where r is the Earthï¿½s radius (in our case the radius at the equator), and w is the angular velocity.

Let a = 9.81 m/s

9.81 = 6.4 x 10

Therefore w = 0.00124 rad/s

This is how fast the Earth would need to rotate to get centripetal acceleration at the equator equal to 9.81 m/s

So if we use this value in this equation:

w = 2/T

Where w is the same as before, the numerator is constant, and T is the time for rotation or the period.

If we put our value of omega (angular velocity) into the equation we find that T = 5074.99 seconds or 1.409 hours. This means that the Earth would need to rotate with a

Answered by: Dan Summons, Physics Undergrad Student, UOS, Souhampton

'The atomic bomb ... made the prospect of future war unendurable. It has led us up those last few steps to the mountain pass; and beyond there is different country.'**J. Robert Oppenheimer**

(*1904-1966*)

All rights reserved. © Copyright '1995-'2017 PhysLink.com