PhysLink.com Logo

Question

Where in the United States is the force of gravity the strongest?
Asked by: Hanni Pilz

Answer

According to the Newton's Law of Gravitation:

F=(GMm)/R2=mg

Where G is the gravitational constant, M is the mass of the Earth, m is the mass of the object, and R is the distance between the of the two objects (in this case, the distance is between you and the center of the Earth.)

Therefore it could be assumed that the closer you are to the center of the Earth (the lower the elevation), the stronger the force of gravity.

If I remember correctly the lowest place in the U.S. is Death Valley at -282 ft (-85.9536m). Given that the mean radius of the Earth is 6.37*106m, we could calculate g, acceleration due to gravity, in Death Valley using the equation above:

g=((6.673*10-11)(5.98*1024))/(6.37*106-85.9536)2 =9.834565215 m/s2

Where G=6.673*10-11
M=5.98*1024

Compare this to the gravitational field calculated using the mean radius: 9.834299811 m/s2

As you can see, the difference is so small, it is insignificant.
Answered by: Loren Chang, Physics Undergrad Student, UC Irvine






Support US

Our server costs have gone up and our advertising revenue has gone down. You do the math! If you find our site useful, consider donating to keep us going. Thanks!


Science Quote

'A theory with mathematical beauty is more likely to be correct than an ugly one that fits some experimental data. God is a mathematician of a very high order, and He used very advanced mathematics in constructing the universe.'

Paul Dirac
(1902-1984)





All rights reserved. © Copyright '1995-'2018 PhysLink.com   Privacy Statement | Cookie Policy