Asked by: Joanna

'The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom.'

So a cesium atomic clock would make just over 9 billion oscillations_per _second (OPS). Finding how many oscillations_per_day (OPD) is just a matter of multiplication:

OPD = OPS x 60 x 60 x 24

Where OPD is oscillations per day, and OPS is oscillations per second.

So we find out that the number of oscillations per second is:

That's 7.94 x 10

Answered by: Yasar Safkan, Ph.D., Sofware Engineer, Noktalar A.S., Istanbul, Turkey

'The mathematician's patterns, like the painter's or the poets, must be beautiful; the ideas, like the colours or the words, must fit together in a harmonious way. Beauty is the first test: there is no permanent place in the world for ugly mathematics.'**Godfrey Hardy**

(*1877-1947*)

All rights reserved. © Copyright '1995-'2017 PhysLink.com