Go to Home Page
You are here
Go to Reference Section
Go to Directories Section
Go to Community Section
Go to Fun Section
Go to Science Store
Go to About PhysLink.com
Top Destinations Menu
 Ask the ExpertsAsk the
Experts

 Physics Job BoardPhysics
Job Board

 Physics and Astronomy Departments DirectoryUniversity
Departments

 FREE Einstein eCardsEinstein
eGreetings

 PhysLink.com Science eStoreScience
eStore




Need an interior designer in the Los Angeles area? Visit: Odeau.com


   Question

When you throw an object into the air, is the initial velocity the same as the velocity just before it hits the ground? If so, why?

Asked by: Robin Pleshek

Answer

First, let's assume you are not taking air resistance into consideration. This is a reasonable assumption because it's obvious that a parachute's velocity just before it hits depends on factors other than just gravity or drop height. Adjusting its size can influence its speed at impact.

Without air friction, an object WILL regain its original upward velocity just before it hits the ground on the way down. The initial velocity on the ground represents KINETIC ENERGY, and the initial height of 0 represents NO POTENTIAL ENERGY. As the object rises, its kinetic energy is gradually converted into potential energy until at its highest point all the original kinetic energy (now zero) has been converted into potential energy. At any point in its travel, TOTAL kinetic and potential energy remains constant.

The process is reversed when the object falls. Starting at maximum potential energy (determined by its maximum height) and zero kinetic energy (not moving), the potential energy gradually gets converted back into kinetic energy until just before it hits the ground. Then, potential energy is zero and it has all the kinetic energy it had at the start.

So the CONSERVATION OF ENERGY is why the two velocities are the same.

Answered by: Paul Walorski, B.A. Physics, Part-time Physics Instructor


go to the top  



All rights reserved. © Copyright '1995-'2009 PhysLink.com