This is a fairly rough estimate, from classroom data. We took squares of aluminum
foil, measured the surface area and mass. By dividing the mass by a known density
value, we obtained the volume of aluminum foil in our sample. By dividing that by the
surface area, we found the thickness of the aluminum foil in cm. (The value was 2.86
*10^-3 cm.) The value converted to be 2.86*10^5 angstroms. Each aluminum atom is about
1.48 angstroms, so we can divide. Assuming that each aluminum atom is stacked directly
on another one (which they aren't, but we can't measure without making this
assumption), we come up with 1.93 * 10^5 atoms thick. There may be different types of
aluminum foil, but these results were fairly precise among our class's data, so I hope
it is at least somewhat helpful.
Answered by: Andy Clemons, High School Student
'The true spirit of delight, the exaltation, the sense of being more than Man, which is the touchstone of the highest excellence, is to be found in mathematics as surely as in poetry.'